# Question about FMOD\_DSP\_PARAMEQ\_GAIN's value

**URL:** <https://qa.fmod.com/t/question-about-fmod-dsp-parameq-gains-value/16798>\
**Category:** FMOD Engine\
**Tags:** cpp\
**Created:** [February 22, 2021, 4:34pm UTC](https://qa.fmod.com/t/question-about-fmod-dsp-parameq-gains-value/16798 "2021-02-22T16:34:41Z")\
**Posts on this page:** 2\
**Page:** 1

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**Author:** ![jiyongman](https://avatars.discourse-cdn.com/v4/letter/j/ebca7d/32.png) [@jiyongman](https://qa.fmod.com/u/jiyongman)\
**Post date:** [February 22, 2021, 4:34pm UTC](https://qa.fmod.com/t/question-about-fmod-dsp-parameq-gains-value/16798/1 "2021-02-22T16:34:41Z")

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According to [this](https://fmod.com/resources/documentation-api?version=2.1&page=core-api-common-dsp-effects.html#fmod_dsp_parameq), **FMOD\_DSP\_PARAMEQ\_GAIN** ’s range is -30~30 and the default value is 0.  
And it also says :  
“Parametric EQ is a single band peaking EQ filter that attenuates or amplifies a selected frequency and its neighbouring frequencies.  
When a frequency has its gain set to 1.0, the sound will be unaffected and represents the original signal exactly.”

To me, setting to 0 makes more sense for the original signal.  
Is it a typo or am I just wrong?  
Also wondering if it’s the same for **FMOD\_DSP\_TYPE\_MULTIBAND\_EQ**.

I know legacy EQs including **FMOD\_DSP\_PARAMEQ** are deprecated so I’m actually working with **FMOD\_DSP\_TYPE\_MULTIBAND\_EQ** ,  
but was reading through the document for more information and saw that sentence, which confused me.

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**Author:** ![joseph](https://yyz2.discourse-cdn.com/flex036/user_avatar/qa.fmod.com/joseph/32/264_2.png) [@joseph](https://qa.fmod.com/u/joseph)\
**Post date:** [February 22, 2021, 11:46pm UTC](https://qa.fmod.com/t/question-about-fmod-dsp-parameq-gains-value/16798/2 "2021-02-22T23:46:47Z")

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> [@jiyongman](#):
>
> To me, setting to 0 makes more sense for the original signal.  
> Is it a typo or am I just wrong?

It’s a typo. That line should say “When a frequency has its gain set to 0, the sound will be unaffected and represents the original signal exactly.”

Thanks for the bug report! We’ll fix this error in our documentation in an upcoming version of our documentation.